Suppose I have a file which is getting appended in every seconds/minutes. At first time I have read whole file and stored the last line number(eg: last_line_numer was : 2000) later I want to read file using 'grep' command to look for a pattern from line number 2001 to end of file. How we can achieve this?

First time I ran below command:

grep 'tracker.php' apache.log | cut -d' ' -f1-8

Now I want to ran above command with specific line number in grep param.

3 Answers 3


You can use tail to output the file from line number 2001 and pipe the result to your command:

<apache.log tail +2001 | grep 'tracker.php' | cut -d' ' -f1-8
  • When I use command like: grep -n 'tracker.php' apache.log | cut -d' ' -f1-8 then it gives line number from apache.log file like: 141007: - - [04/Apr/2019:09:52:01 -0400] "GET /tracker.php?q=1&p=2 HTTP/1.1" 141008: - - [04/Apr/2019:09:52:01 -0400] "GET /tracker.php?q=1&p=2 HTTP/1.1" but when I use: <apache.log tail +141009 | grep -n 'tracker.php' | cut -d' ' -f1-8 then it give line number 1,2,3 but not 141009, 141010, 141011. How can I get this?
    – groy
    May 4, 2019 at 20:42
  • cat -n apache.log | tail +2001 | grep -o '.*tracker.php[^"]*"'if we take the logfile from your other question
    – Freddy
    May 4, 2019 at 21:56
  • I am not able to use this command by storing value in variable , here is ref: stackoverflow.com/questions/56066661/… What can be issue here?
    – groy
    May 10, 2019 at 1:51

You can use

awk 'NR<2001 {next} /tracker.php/ {print NR, $1,$2,$3,$4,$5,$6,$7,$8}' apache.log


awk 'NR<2001 {next} /tracker.php/ {print NR, $0}' apache.log | cut -d' ' -f1-9

which will also display the original line numbers of the matching lines in the file.

  • 1
    Or awk 'NR>2000&&/tracker.php/ {NF=8; print NR,$0}' May 5, 2019 at 4:59

Using sed:

sed '1,2000d; /tracker\.php/!d' | cut -d ' ' -f-8

That is, discard lines 1 through to 2000 (inclusively), and then also discard any line not containing the string tracker.php. Send the rest of the lines through cut.

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