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I have a shell script with the following contents. I call it with ./script.sh. Echo successfully runs, but not when I try to save its output to a variable. The same is true for all commands I've tested so far; ls, pwd, node, etc…

#!/bin/zsh

echo foo
# foo

output=$("echo foo")
# command not found: echo foo

How come?

EDIT: Fix: the last echo is inside a string!

  • The only way I'm able to reproduce this is if I quote echo foo like: output=$('echo foo'). Or if I escape the space like output=$(echo\ foo). – Jesse_b Mar 23 at 14:33
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    can't reproduce here; do you have something odd in your zsh profile? – Jeff Schaller Mar 23 at 14:33
  • I'm sorry, The last echo is supposed to reside in a string. – Audun Olsen Mar 23 at 14:38
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    running "echo foo" would result in a similar error; what's your goal? – Jeff Schaller Mar 23 at 14:39
  • Simply saving the output to a variable. But I see that it being inside a string may be my mistake… – Audun Olsen Mar 23 at 14:41
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It seems like you found the issue. You should quote only the string passed to echo and not the entire command itself:

output=$("echo foo")

Should instead be:

output=$(echo "foo")

If you want the output variable to contain the literal string echo foo then you should just set it as:

output='echo foo'

but could also do:

output=$(echo 'echo foo')
  • Thank you, this works. An additional question; if i replace echo with node, which was my initial goal, calling a node-script. I get command not found: node despite node being inside my $PATH variable. Which I checked by echoing path from inside the script. Thoughts? – Audun Olsen Mar 23 at 14:47
  • Without seeing the command you're attempting to execute and your path I can't really speculate. – Jesse_b Mar 23 at 15:02
  • node script.js succeeds, output=$(node script.js) fails. Falls perfectly in line with the question title, actually. – Audun Olsen Mar 23 at 15:14
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As one might expect commands inside parentheses creates a subshell. But $() is not what you might think. It does not return the output of a command as a string it substitutes the output of a command into the shell. If you want proof try this: $(echo "echo 123")

Instead you want to use double quotes to capture it into a string instead of the array (the output split by spaces) being run on the shell.

output="$(echo foo)"

Note this isn't an issue specific to zsh it applies to bash as well.

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