I would like to search for files that would not match 2 -name conditions. I can do it like so :

find /media/d/ -type f -size +50M ! -name "*deb" ! -name "*vmdk"

and this will yield proper result but can I join these 2 condition with OR somehow ?


You can do this using a negated -regex, too:-

 find ./ ! -regex  '.*\(deb\|vmdk\)$'
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    Note that -regex is less portable than -name. – jw013 Oct 12 '12 at 13:54

yes, you can:

find /media/d/ -type f -size +50M ! \( -name "*deb" -o -name "*vmdk" \)

Explanation from the POSIX spec:

! expression : Negation of a primary; the unary NOT operator.

( expression ): True if expression is true.

expression -o expression: Alternation of primaries; the OR operator. The second expression shall not be evaluated if the first expression is true.

Note that parenthesis, both opening and closing, are prefixed by a backslash (\) to prevent evaluation by the shell.

  • 1
    If you're doing -exec or any other action on the find results, remember to parenthese \( \) the whole criteria, otherwise -exec will apply only to the last -or-ed criterion. To work on all of them, parenthese them: find \( <criterion> -o <criterion> \) -exec <command> – Victor Sergienko Jun 13 at 20:38

You was close to solution:

find /media/d/ -type f -size +50M -and ! -name "*deb" -and ! -name "*vmdk"

You can combine following logic operators in any sequence:

-a   -and      - operator AND
-o   -or       - operator OR
!              - operator NOT

You can use regular expressions as in:

find /media/d -type f -size +50M ! -regex '\(.*deb\|.*vmdk\)'

Backslash is the escape character; . matches a single character, and * serves to match the previous character zero or more times, so .* means match zero or more characters.

  • 1
    Adding an explanation would make your answer better. – N.N. Oct 12 '12 at 14:01
  • You're right. Added some explanations. – Francesco Turco Oct 12 '12 at 14:09

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