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I would like to search for files that would not match 2 -name conditions. I can do it like so :
find /media/d/ -type f -size +50M ! -name "*deb" ! -name "*vmdk"
and this will yield proper result but can I join these 2 condition with OR somehow ?
yes, you can:
find /media/d/ -type f -size +50M ! \( -name "*deb" -o -name "*vmdk" \)
Explanation from the POSIX spec:
! expression : Negation of a primary; the unary NOT operator.
( expression ): True if expression is true.
expression -o expression: Alternation of primaries; the OR operator. The second expression shall not be evaluated if the first expression is true.
Note that parenthesis, both opening and closing, are prefixed by a backslash (\) to prevent evaluation by the shell.
-exec or any other action on the find results, remember to parenthese \( \) the whole criteria, otherwise -exec will apply only to the last -or-ed criterion. To work on all of them, parenthese them: find \( <criterion> -o <criterion> \) -exec <command>
Jun 13, 2019 at 20:38
You can do this using a negated -regex, too:-
find ./ ! -regex '.*\(deb\|vmdk\)$'
find -name. Serge's answer answers that.
You were close to a solution:
find /media/d/ -type f -size +50M -and ! -name "*deb" -and ! -name "*vmdk"
You can combine the following logic operators in any sequence:
-a -and - operator AND
-o -or - operator OR
! - operator NOT
find command. Note that -a is the default operator if an explicit operator is missing. Also note that if you use -o, there must be a logical grouping of the two name tests. You do this with \( ... \).
You can use regular expressions as in:
find /media/d -type f -size +50M ! -regex '\(.*deb\|.*vmdk\)'
Backslash is the escape character; . matches a single character, and * serves to match the previous character zero or more times, so .* means match zero or more characters.