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I have a folder structure like this:

/ms/files/a/
/fb/files/a/
/db/files/a/

It should be like this:

/ms/files/b/
/fb/files/b/
/db/files/b/

I can find the folders I need to move or rename using

find . -path "*/files/a" -type d

But how do I rename the results?

  • 1
    Is the leading directory always one level deep, or do you need the find because there's, for example, /ms/other/directory/files/a? – Jeff Schaller Feb 27 at 16:29
  • It's always one level deep – Lennart Feb 27 at 16:34
  • Found it: should use the full path and * as wildcard. Thanx for your help @JeffSchaller! – Lennart Feb 27 at 16:46
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One way:

for d in /*/files/a/
do
  mv "$d" "${d%a/}b"
done

... which uses * to match all of the initial "client" top-level directories, followed by the required /files/a/ subdirectory structure. It then uses parameter expansion to strip the trailing a/ off of each one and then "replace" it with a b for the rename.

  • Thanks! But... I get an error: mv: cannot stat `?/files/a/': No such file or directory. When I use a hardcoded path it works, problem seems with the ? – Lennart Feb 27 at 16:25
  • I used the "/client" portion from your question, where I assumed that each "client" directory had a single digit after it. Are those your actual directory names? – Jeff Schaller Feb 27 at 16:26
  • Also: the /client1/ part is the name of a client (e.g. /microsoft/files/a, /google/files/a, etc). – Lennart Feb 27 at 16:26
  • Then I was inadvertently distracted by the similar pattern. Could you edit the question to describe the commonalities & differences in the files /directories you want to match? Thanks! – Jeff Schaller Feb 27 at 16:28
  • @Lennart, I've reworked the answer given the actual directory structure. – Jeff Schaller Feb 27 at 16:45
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A hacky solution:

eval $(find . -path "*/files/a" -type d -print | xargs -n1 -exec echo | sed 's/\(.*\/\)\(.*\)$/mv \1\2 \1b;/')

Sed creates the arguments for the mv command. The output is then eval'ed.

If we remove eval $(), it looks like this executed on three test folders in the path:

$ find . -path "*/files/a" -type d -print | xargs -n1 -exec echo | sed 's/\(.*\/\)\(.*\)$/mv \1\2 \1b;/'
mv ./client1/files/a ./client1/files/b;
mv ./client2/files/a ./client2/files/b;
mv ./client3/files/a ./client3/files/b;
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Done by below method and it worked fine

for i in /ms/files/  /fb/files/ /db/files/; do find $i -type d; done| sed -n '/a$/p'| awk '{print "sudo mv" " " $1 " " substr($1,1,10)"b/"}'|sh

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