Grep/Awk for Value Between

Question

So I have a text file with lines like this:

http://sg.ovies.m/.ss/ (Status: 200) [Size: 128]
http://sg.mo.v/.dev/ (Status: 200) [Size: 12328]
http://som.b/.hal/ (Status: 200) [Size: 1238]
http://m.cb/.ho/ (Status: 200) [Size: 0]
http://sm.jo/.hK/ (Status: 200) [Size: 0]`

I would like to only grep the lines where Size is between 1 and 100.

So the output would be:

http://sg.ovies.m/.ss/ (Status: 200) [Size: 128]
http://sg.mo.v/.dev/ (Status: 200) [Size: 12328]
http://som.b/.hal/ (Status: 200) [Size: 1238]

How can it be done using grep or awk?

Answer 1

Awk makes this easy:

awk '{size=$5; sub(/]/, "", size); size=size+0; if (size <= 100 && size >= 1) {print $0 } }' file_to_read.txt

Writing this in a more friendly way:

awk '{
    # create a new variable "size".
    # items are separated by spaces, we need the 5th item
    size=$5;

    # remove the trailing "]"
    sub(/]/, "",  size);

    # make sure size is an int
    size=size+0;

    # Choose rows with seize between 1 and 100
    if (size <= 100 && size >= 1) {
        # print the whole line
        print
    }

    }'  file_to_read.txt

Answer 2

Considering that : character occurs in only 3 places in your input, we can use that as field separator, then extract the number for comparison via substring (with accounting for leading space):

awk -F':' '{size=substr( $NF,2,length($NF)-2 ); if((size>=1)&&(size<=100)) print }' input.txt

Note that you've asked for "Size: is between 1 and 100." However your sample output reads as "Size greater than 1". If that is the case, then if statement can be reduced to if(size > 1) print

Answer 3

The following pattern should do it:

grep -E 'Size: (?:100|[1-9]|[0-9]{2})]' test

I tells grep to use extended RegEx syntax (-E) and tries to match either 100 or a value from 0 to 99 following Size: