1

When I run this:

find . -name "my.log*.gz" -print | \
parallel zgrep -e "\(text1\|text2\).*Exception"

to find all lines that match /(text1|text2).*Exception/ in all files in the folder, I get this error message:

zsh:1: no matches found: (text1|text2).*Exception

From the error message, I think (text1|text2).*Exception is being treated as a file name. What am I doing wrong here?

  • Just to be sure: what parallel command are you running? The command from the 'moreutils' package, or the 'GNU parallel' command from the 'parallel' package? – ozzy Jan 15 at 20:41
  • Note that grep expects one or more filenames as arguments on the commandline, or file contents on stdin. In contrast, your command feeds filenames on stdin (via the pipe), which will not work. In addition, if you are using the parallel command from the moreutils package, the syntax is off. – ozzy Jan 15 at 21:03
1

You need more quoting:

find . -name "*.gz" -print |
  parallel -q zgrep -e "\(text1\|text2\).*Exception"

Use -vv and --dr to see what is really being run.

0

Use -E for extended regex

find . -name "my.log*.gz" -print | \
parallel zgrep -E "\(text1\|text2\).*Exception"
0

If you are using the parallel command from the moreutils package, your command could be simplified like this:

parallel zgrep -e "\(text1\|text2\).*Exception" -- my.log*.gz

This will run parallel instances of zgrep, one for each file matching the shell pattern my.log*.gz. Note that the pattern is expanded by the shell before the command is executed. Hence there is no need for a separate invocation of find.

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