I'm running two instances of omxiv (Omx Image Viewer). The first instance acts like a background image, and the second instance acts as a slideshow. My question is how can I specifically kill the second instance?

Small note: The second instance will always be opened after the first instance.

I was thinking about killing it by pid, but I am not sure if it will have the same pid after the reboot, therefore this might not work.

Right now I am calling:

pkill -9 omxiv

which is terminating both instances.


pkill has a -n flag that will make it only affect the most recently started ("newest") matching process.

pkill -n omxiv

If the omxiv process is well behaved, there is no need to use -9.

There is also a -o flag that will make pkill send a signal to the oldest matching process.

Note that using pkill -n will always kill the newest instance. If you have three processes, it will kill the third, not the second (as per title of question).

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  • That's exactly what I needed, it works great. Thanks for explanation – Dino Jan 13 '19 at 11:30
  • According to the man page, this also works on Debian and Ubuntu. – kasperd Jan 13 '19 at 19:52
  • 1
    @kasperd I was a bit careful, because OpenBSD pkill has some options not implemented on Linux systems, for example -q to be quiet. – Kusalananda Jan 13 '19 at 20:29

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