The document of sed states that d will:

Delete the pattern space; immediately start next cycle.

If sed is run without -n, will sed auto print the pattern space after a d command? I know at this situation, the pattern space is empty. So it's no differences to print or not. But I'm just curious.

I have this example:

root@u1804:~# seq 10 | sed -r '/5/d'

As you can see, there is no 5. It's because the d caused the execution directly to the next cycle or the auto print pattern space prints an empty string?


Yes, d restarts the cycle so no auto-printing. It's easy to see that if you attempt to append to the pattern space after a d command e.g via G or s/^/STUFF/ nothing gets printed...
Try seq 3 | sed '1h;2d;2G' - it will not print 1 twice even though you save it via 1h and then try to append it via 2G for the simple reason the last command is never executed - everything that follows after d (including auto-printing) is ignored (for the current address, that is).
The standard is pretty clear:

If no commands explicitly started a new cycle, then at the end of the script the pattern space shall be copied to standard output (except when -n is specified) and the pattern space shall be deleted.

It's also in the manual that you quoted:

By default sed prints all processed input (except input that has been modified/deleted by commands such as d)

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