Count the number of files and folders containing a certain string

Question

Let's say I'm in the Desktop directory and want to count the number of files and directories whose name is exam. It should also count the files containing the string exam. So to sum it up I need to:

1. Count the directories with the name exam
2. Count the files with the name and content exam

Here is what I've tried so far.

ls -l | grep -r "exam" | wc -l 

But this command counts only files with the content exam. What if I have a couple of directories: exam1, exam2, exam3, and a couple of .txt files exam1.txt, exam2.txt, exam3.txt, and want to count them?

Answer 1

Using find, treating directories and non-directories differently, getting the counts for directories and non-directories separately:

find . -name '*exam*' \
    \( \(   -type d -exec echo directory \; \) -o \
    \(    ! -type d -exec grep -q -wF exam {} \; -exec echo file \; \) \) |
sort | uniq -c

This would find things in or below the current directory whose names contains the string exam. If the thing is a directory, then the string directory is outputted. Otherwise, if the thing is a non-directory, and if its contents contains the word exam, then the string file is outputted. The sort and the uniq -c at the end would sort and count the number of files and directories found that matched the criteria.

Note that the test on the names may match names that contain exam as a substring, as in example for example. The grep on the files uses -w which will make it more likely that a word is matched, and not a substring.

Answer 2

I have done by below 2 commands

To count directories

find  path -type d -iname "exam[0-9]" | wc -l

To count number of files with condition it should have content exam in the file

find  path -type f -iname "exam[0-9]" -exec grep 'exam' {} \;|wc -l

Answer 3

Try this,

For folders:

 ls -lR * | awk -F '[ /]' ' !/^-/ && !/^d/{if ($NF ~ "exam" ) print $NF}' | wc -l

For files:

 ls -lR * | awk  '/^-/ {if ($NF ~ "exam" ) print $NF}'  | wc -l

Answer 4

The following script achieves what you want:

i=0
for file in *exam*
do
  if [ -d "$file" ] || [ -n "$(sed -n '/exam/{p;q}' -- "$file")" ]
  then
    i=$((i+1))
  fi
done
echo "Number of files: $i"

It loops over all the files whose name contains exam, and for each such file it checks whether it is a directory or it contains the string exam, and if it does, the script increases the counter by one.

Edit: I probably misunderstood your question and you want to count directories and files separately. In that case, modify the script to

i=0;j=0
for file in *exam*
do
  if [ -d "$file" ]; then
    i=$((i+1))
  elif [ -n "$(sed -n '/exam/{p;q}' -- "$file")" ]; then
    j=$((j+1))
  fi
done
echo "Number of directories: $i"
echo "Number of regular files: $j"