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I'm trying to start multiple processes at the same time using a for loop. I want each to be created in it's own console window. So far i have the following:

for i in {1..5}; do konsole -e "./program arg1 arg2"; done 

However , this simply runs them one after another, where i want them to run concurrently. I've tried using '&' but i can't get i to play nicely with the loop.

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    Replace the ; before done with &. But first check whether konsole -e "./program arg1 arg2" does what you think it does. – AlexP Dec 14 '18 at 23:20
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    @AlexP You should write that up as an answer. I would have upvoted. – Sparhawk Dec 15 '18 at 3:44
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A background task is started by putting a & at the end of the command. Your loop would start konsole in the background if you wrote it as

for i in {1..5}; do
    konsole -e "./program arg1 arg2" &
done

or, on a single line,

for i in {1..5}; do konsole -e "./program arg1 arg2" & done

The & is a command terminator, just like ; (and newline and a few others), so it replaces the ; that you originally had there.

Would you want the script to wait for the started background tasks to finish, add a wait at the end:

for i in {1..5}; do konsole -e "./program arg1 arg2" & done; wait

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