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As you can see in the picture attached screen shot

After I used the sort command to sort a VERY large wordlist file I then split them up using the Split command. From there I confirmed that the listed words are in a-z order.

I then ran the sort -u command and noticed that it was not removing unique words. (It was removing some as I could see the files were a little smaller, but not all.)

What am I doing wrong?

Overall goal: my over all goal is to take all my wordlists and put them into one large file (25gig), then sort and remove any unique words (cutting this by 40% or so) and then split up the files into manageable sizes. No Windows programs or Linux commands worked.

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  • 6
    Copy and paste output instead of posting screenshots. Text is much easier to deal with than images, especially when your question has nothing to do with graphics. – jw013 Sep 20 '12 at 20:52
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    Are you sure that there are no invisible characters at the end of the words? Like spaces. – Karlson Sep 20 '12 at 20:57
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sort -u removes unique lines. So, the a potential problem is that these three lines are not the same, and sort -u will leave all of them:

foo
foo 
foo 

No matter how closely you look, its hard to notice why. That is, unless you take a hex dump, with xxd for example:

0000000: 666f 6f0a 666f 6f20 0a66 6f6f e280 820a  foo.foo .foo....

0x0a is newline, if you're not familiar with hex dumps. So the three "foo"s are:

666f 6f         0a
666f 6f20       0a
666f 6fe2 8082  0a

Aha! That's actually foo, foo<SPACE> (the 0x20), and foo<EN-SPACE> (the 0xe28082, which is U+2002 encoded in UTF-8).

You've probably got something similar going on. You need to use a hex editor, or a text editor set to show invisible characters. For example, here is what it looks like in gvim with :set list. I've just typed in the ga command to see what the character under the cursor is, revealing that its U+2002. You can also see how the end of line ($) isn't where you expect on the two with spaces after them:

screenshot of gvim demonstrating :set list

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  • well this is what i thought too... so i loaded it in a text editor and saw nothing (checking so see if there were spaces). HOWEVER, i did NOT turn on show hidden characters. so heres the followup question.... is there any script that would delete these after the word? I dont know how to intelligently ask that question however you understand my overall goal. Any suggestion would be great. :( I really want to make this the most efficient wordlist for running through audits. – Alex Sep 20 '12 at 21:35
  • @Alex I'm unsure from your comment, when you tried it with show hidden characters (or even better, a hex editor) did it become clear what is going on? – derobert Sep 20 '12 at 21:37
  • ^ sorry, had to edit the comment. it submitted and cut me off – Alex Sep 20 '12 at 21:39
  • @Alex I think you could do that fairly easily with sed or perl. For example, piping through perl -p -e 's/\s+$//' – derobert Sep 20 '12 at 21:41
  • @Alex also, you'd ask that as "trimming whitespace from the end of each line" or similar. Also, as a final note, if you're doing matches against this huge wordlist, and need it to be efficient, there are algorithms for that. Probably a question for Stack Overflow. – derobert Sep 20 '12 at 21:46

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