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I am expecting that variable url will be resolved in $() but I am getting variable of variable as url and not "http://testing.com"

url="http://testing.com"

echo "Fetching from ${url}"

some_var=$(python somePythonScript.py url)
  • @JeffSchaller thanks for reminding, I was waiting on 4 mins to finish and I moved to another tab. – Vishrant Dec 3 '18 at 7:22
5

You correctly referenced the variable here:

echo "Fetching from ${url}"

So do the same thing here:

some_var=$(python somePythonScript.py "${url}")

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