I have a file that has the following format
1|3
7|10
11|16
and I would like with a script to have the following format
1
2
3
7
8
9
10
11
12
13
14
15
16
Basically I have a range and in the first column is the start number and in the second column the end number and I would liked to have the output file with all the numbers from that range in a new line .
With awk:
awk -F'|' '{for (i = $1; i <= $2; i++) print i}' < input > output
{for (i=$1; i<=$2; i++) print i} as it doesn't have to rebuild $0 for each iteration of the loop.
– glenn jackman
Nov 22 '18 at 14:26
for loop is faster indeed, so I'm going to follow your recommendation.
– Stéphane Chazelas
Nov 22 '18 at 14:37
tr -s \| " " < file.txt |xargs -l1 seq > output.txt
Assuming the values are strictly valid base 10 numbers (if not, clean them):
$ cat ./script.sh
#!/bin/bash
while IFS='|' read a b
do until ((a>b))
do printf '%d\n' "$((a++))"
done
done
$ ./script <infile >outfile
