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I want to write a script for login statistics. I want to count how many times a user logged in, and then display them in ascending, or descending order, given by the end user. The problme being, i don't know how to write a script that could count how many times a user logged in. I have to use the last command.

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    Can't you do last $username for every user, and count the lines being returned? You will have to truncate the last 2 ones though. Also, be warned that the wtmp file only holds records for a specific timeframe. – Panki Nov 19 '18 at 16:16
  • #!/bin/bash echo '1 - ascending, 0 - descending, please choose:' read x echo 'how many lines do you need?:' read y if [ $x -eq 1 ]; then echo last >> last.txt fi after I have the last.txt file, i need to count how many times one user logged in, then put the data in ascending/descending order. At the end, I have to display A certain amount of lines, strating from 1. Can't really figure out how to do it.. – Bakos Dominik Nov 19 '18 at 16:38
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#!/bin/bash
userlist=$(cat /etc/passwd | cut -d : -f 1)
for user in $userlist; do
        timesloggedin=$(last $user | head -n -2 | wc -l);
        echo $timesloggedin $user;
done | sort -r

This gets the name of ALL the users on the system, including daemon accounts etc. If you don't want that, supply userlist with a list of your usernames. To get the output in ascending order, drop the -r flag to sort.

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