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I want to read 9th column of text file with '~' delimiter and need to retrieve data from for the corresponding 11th column which resides in a table. that data i need to replace in 11th column of the file which is having NULL values currently.

How to achieve this in unix.

col1~col2~col3~col4~col5~col6~col7~col8~col9~col10~col11~col12~col13

data1~data2~data3~data4~data5~data6~data7~data8~data9~data10~~data12~data13

in the data data11 is null . so i want to take the corresponding value for data9 and replace the data11.

Thanks

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If you want only to copy column 9 to column 11 this can be done with script like this:

awk 'BEGIN {FS="~"; OFS="~"}{$11=$9; print}' <filename>

If the first file have only one line you can do something like:

awk -v val=$(awk -F\~ '{print $9}' <filename b>) 'BEGIN {FS="~"; OFS="~"}{$11=val; print}' <filename a>
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  • otherwise if i want to replace the data from col2 in b file to col11 in a file. how can i achieve this. – Lakshminarayana Reddy Nov 13 '18 at 13:52
  • @LakshminarayanaReddy, please clarify this explicitly in question. Its very unclear. I will add something which you can use but w/o precise question this may or may not work. Is it file a only one line or you want to to replace from multiline file? – Romeo Ninov Nov 13 '18 at 13:55
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Not sure I fully understand. Would this come close?

awk -F~ '!$11 {$11 = $9}1' OFS="~" file
col1~col2~col3~col4~col5~col6~col7~col8~col9~col10~col11~col12~col13
data1~data2~data3~data4~data5~data6~data7~data8~data9~data10~data9~data12~data13
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