I have a bash script that looks like this:

SOME_VARIABLE=$(readlink -f $(dirname ${BASH_SOURCE[0]}))

I need to source it from a zsh shell as I need to have all the environment variables it defines.

The issue is that I get this error message because of BASH_SOURCE:

dirname: missing operand
Try 'dirname --help' for more information.
readlink: missing operand
Try 'readlink --help' for more information.
Invalid location:

Constraints: I cannot modify the script.

Question: Can I source a bash script containing BASH_SOURCE from zsh?

  • 2
    Source it from a bash shell, then start the zsh shell. – Kusalananda Nov 1 '18 at 10:31
  • 1
    . <(awk '{gsub(/\${BASH_SOURCE\[0\]}/, FILENAME); print}' /path/to/the/bash/script) – mosvy Nov 1 '18 at 11:44
  • @mosvy that works for me, I would mark it as accepted if it was an answer instead of a comment – rual93 Nov 1 '18 at 11:54

Instead of doing . /path/to/that/script.bash, do:

BASH_SOURCE=/path/to/that/script.bash emulate ksh -c '. $BASH_SOURCE'

emulate ksh -c '...' runs the code in ksh emulation (so that for instance, array indices start at 0 like in bash) and also makes sure all functions defined within inherit that emulation mode.

$BASH_SOURCE in bash refers to the file being sourced, so we preseed that variable with the path of the script.

The zsh equivalent of that bash code would be:

export SOME_VARIABLE=$0:h:P

(:h giving the head like in csh (the equivalent of dirname), and :P the equivalent of GNU readlink -f).

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