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I am trying to write a sed expression to detect lines similar to this:

s0:12345:respawn:/sbin/agetty -8 -s 115200 ttyS0 linux

and replace the ttys0 with something_else

I do not want to detect commented out lines (beginning with #)

I can replace the whole line, but how to I just replace the substring, leaving the rest of the line intact ?

3 Answers 3

8

One way to do this is as follows:

echo 's0:12345:respawn:/sbin/agetty -8 -s 115200 ttyS0 linux' | 
    sed -e '/^[^#]/ s/ttyS0/foo/'
0

Match the part before ttyS0 and those after ttyS0, also check if line doesn't begin with #:

sed 's/^[^#]\(.*\)ttyS0\(.*\)/\1something\2/'

Result:

%> echo "s0:12345:respawn:/sbin/agetty -8 -s 115200 ttyS0 linux" | sed 's/^[^#]\(.*\)ttyS0\(.*\)/\1something\2/'
0:12345:respawn:/sbin/agetty -8 -s 115200 something linux
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  • 2
    You don't need last group and \2 at all. Also if it is possible it's much better do not use backreference cause usually it eats too many resources.
    – rush
    Commented Sep 11, 2012 at 15:35
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If it always starts with s[number]colon you could do (with GNU sed):

sed -r '/^s[0-9]+:/s/ttyS0/something_else/' infile

Which changes any line that starts with the regex, adapt to suit your needs.

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