0

This works

echo "         HELLO   x=10" |sed 's/ *\HELLO \+/HELLO /g'

removes continuous space before hello and after word "HELLO"

but this doesn't

echo "         WHERE     x=10" |sed 's/ *\WHERE \+/WHERE /g'

i have tried to escape \w with \w like below

echo "         WHERE     x=10" |sed 's/ *\\"WHERE" \+/\"WHERE" /g'

but even this is not working. What is wrong.

3

Why are you escaping the H and the W ?

\H and \W have specific meanings, and they are different from H and W .

echo "         WHERE     x=10" |sed 's/ *WHERE \+/WHERE /g'
2

Just drop the \ before the words.

echo "         WHERE     x=10" |sed 's/ *WHERE \+/WHERE /g'
WHERE x=10

The \ in regular expressions is used as an escape character for various type of matches.

The \w is used to find a word character, i.e. a character from a-z, A-Z, 0-9, including the _ (underscore) character.

As an upper case version negates a match, your \W means don't match a single character, which obviously makes the regex fail for your input string.

Try for example:

echo "         {HERE     x=10" |sed 's/ *\WHERE \+/WHERE /g'
WHERE x=10

it works because { is matched by \W (as { is NOT a word character)!

  • Thanks ,can't upvote , don't have that reputation . actually \ worked with HELLO but not with WHERE and confused me. – etl_devs Oct 10 '18 at 15:13
  • 1
    @etl_devs that's because \h matches whitespace and then \H not whitespace which means the H in HERE gets matched – Mr Shunz Oct 10 '18 at 15:30

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