4

Basically, I am running:

nohup ./executable &> /tmp/out.log &

In order to make sure the process is running I ran the command:

tail -f /tmp/out.log

But the only thing I can get from tail is "nohup: ignoring input", and once killing the process that previously started I can see the contents of out.log

5

Run your program as:

nohup stdbuf -oL ./executable &> /tmp/out.log &

stdbuf can change the default buffering.

4

Your executable is using buffered output, so you will only see something with tail if more than one block of output is produced. The size of such a block will be 4k or more.

If you wrote the executable yourself, change the output to line buffered or to not buffered.

  • +1 Or add an instruction to flush stdout ; nonetheless we cannot give a better answer to such a vague question. – Rui F Ribeiro Sep 15 '18 at 20:56
  • makes sense, the executable is from the LoRa device provider. Is there an easy workaround? thanks for the response! – 9uzman7 Sep 15 '18 at 20:59
  • You can allocate a pty and give that to the executable. Most programs use line buffered for a tty. Your program also does if you see immediate output if you run it directly from the shell. – RalfFriedl Sep 15 '18 at 21:02

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