What's the portable way to delete the first line1 from the pattern space ?
gnu sed I can do
but as far as I know this (using
\n in a bracket
 expression) is not portable.
Practical example: here,
sed prints the last section of the file including the delimiter via portable code. I'd like to remove the first line from the pattern space so as to exclude the delimiter and do that in a portable manner. With
gnu sed it's simple:
sed 'H;/===/h;$!d;//d;x;s/[^\n]*\n//' infile
1: Obviously this should be done without restarting the cycle of commands...