Find and sort by file size

Question

I have this command to find files larger than 2 KB and sort by size:

find . -size +2k -name *.log -printf "%p \t%k kb\n" | ls -lS

but the ls -lS gives the files that are less than 2 KB also.

How can I display the names and sizes of the files that are larger than 2 KB, sorted by size?

Answer 1

Try

 find . -size +2k  -printf "%p \t%k kb\n" | sort -k2n

Answer 2

The ls command will list the current directory, not read something from stdin.

Use

find . -size +2k -name *.log -printf "%s %p \t%k kb\n" | sort -n | sed -e '/^[0-9]* //'

Answer 3

With zsh:

zmodload zsh/stat
printf '%s\n' **/*.log(DLK+2oLe'[
  stat -A blk +block -- $REPLY && REPLY+=" $((blk / 2)) KiB"]')

That reports the disk usage of the log files whose size is greater that 2048, ordered by size.