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I want to calculate a directory size with all its subdirectories. But I had made some of the subdirectories to mount from a mount point. (using mount -B/--bind)

when I use du -hks the returned size includes the mounted directories. Is there a way to eliminate their size from the result?

Edit: The Directories I calculate size are all in the same location. There is a Main directory with shared content for all other directories (This contains all the mount points) and Directories have some individual files. The goal is to calculate the individual files size.

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du -x (at least GNU and busybox du) is fooled by Linux bind-mounts because files have the same device-id, so you'd need to prune the mount-points by hand. With GNU du:

du -xhs --exclude=./bind/mount/point

Alternatively, you could use GNU find to find the files and print their disk usage, calling the mountpoint command to know which directories to prune (which are bind-mounts). Then use awk to do the sums (counting hardlinks only once like du does):

find . -xdev ! -name . -type d -exec mountpoint -q {} \; -prune -o \
       -printf '%i %b\n' |
  awk '!seen[$1]++ {s+=$2}
       END{printf "%.17g\n", s * 512}' |
  numfmt --to=iec

That's quite inefficient though in that it needs to run the mountpoint command for each directory (note that it's also possible to bind-mount non-directory files, we're assuming it's not done to avoid running mountpoint on each file).

  • is there any other command I could use instead of du? – Ali Shadloo Jul 30 '18 at 11:53
  • @AliShadloo, see edit – Stéphane Chazelas Jul 30 '18 at 12:15
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man du:

   -x, --one-file-system
          skip directories on different file systems
  • but the mount points are directories from the same file system. – Ali Shadloo Jul 30 '18 at 10:38

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