Can I grep for 2 patterns and have them listed side by side?

Question

Ubuntu 16.04

bash -version  
GNU bash, version 4.4.0(1)-release (x86_64-unknown-linux-gnu)

I would like to grep for 2 patterns and then have them listed side by side. At the moment, this is what I have:

root@tires ~ # grep -e tire_id -e appID /path/to/*/vehicle/production.json
/path/to/000001_000002/vehicle/production.json:    "tire_id": "1305436516186552",
/path/to/000001_000002/vehicle/production.json:        "appID": "1164562920689523",
/path/to/000001_000079/vehicle/production.json:    "tire_id": "1815123428733289",
/path/to/000001_000079/vehicle/production.json:        "appID": "18412365908966538",
/path/to/000001_000088/vehicle/production.json:    "tire_id": "138477888324",

This is what I would like to have although anything similar would work actually.

root@tires ~ # grep -e tire_id -e appID /path/to/*/vehicle/production.json
/path/to/000001_000002/vehicle/production.json:    tire_id: 1305436516186552, appID: 1164562920689523
/path/to/000001_000079/vehicle/production.json:    tire_id: 1815123428733289, appID: 18412365908966538

File example here:

{
    "socal": "https://xxx.xxxxx.xxx",
    "ip": "xxx.xxx.xxx.xxx",
    "tire_id": "213275925375485",
    "client": {
        "platform": "xx",
        "clientID": "xxxxx",
        "serviceID": "xxxxx",
        "service_id": XXXX,
        "vendor": "default"
    },
    "locale": "en_US",
    "cdc": {
        "appID": "233262274090443",
        "isdel": "ORdiZBMAQS2ZBCnTwZDZD",
    },
    "attachments": {
        "output": "attachments",
        "public": false,
    },
}

Answer 1

The right way with jq tool for a valid JSON documents:

Sample file1.json:

{
    "socal": "https://xxx.xxxxx.xxx",
    "ip": "xxx.xxx.xxx.xxx",
    "tire_id": "213275925375485",
    "client": {
        "platform": "xx",
        "clientID": "xxxxx",
        "serviceID": "xxxxx",
        "service_id": "XXXX",
        "vendor": "default"
    },
    "locale": "en_US",
    "cdc": {
        "appID": "233262274090443",
        "isdel": "ORdiZBMAQS2ZBCnTwZDZD"
    },
    "attachments": {
        "output": "attachments",
        "public": false
    }
}

---

Sample file2.json:

{
    "socal": "https://xxx.xxxxx.xxx",
    "ip": "xxx.xxx.xxx.xxx",
    "tire_id": "1305436516186552",
    "client": {
        "platform": "xx",
        "clientID": "xxxxx",
        "serviceID": "xxxxx",
        "service_id": "XXXX",
        "vendor": "default"
    },
    "locale": "en_US",
    "cdc": {
        "appID": "1164562920689523",
        "isdel": "ORdiZBMAQS2ZBCnTwZDZD"
    },
    "attachments": {
        "output": "attachments",
        "public": false
    }
}

---

And the solution itself:

jq -r 'input_filename + " tire_id: \(.tire_id) appID: \(.cdc.appID)"' file*.json

The output:

file1.json tire_id: 213275925375485 appID: 233262274090443
file2.json tire_id: 1305436516186552 appID: 1164562920689523

Answer 2

You can do this with grep but it's rather conplicated and Roman's answer is actually better.

Your example contents are just from one file so there is only once instance of tire_id and appID.

Use this:

echo $(echo /path/to/production.json && egrep "tire_id|appID" /path/to/production.json | sed -e 's|"||g' | sed -e 's|,||2') && echo $(echo /path/to/production2.json && egrep "tire_id|appID" /path/to/production2.json ) | sed -e 's|"||g' | sed -e 's|,||2'

echo puts everything on the same line with command substitution.

egrep does the same thing as grep -e but allows you to put all the strings together separated by | instead of having to use -e string each time.

sed -e 's|"||g' removes the apostrophes.

sed -e 's|,||2 removes the comma from the end of the value for appID which is what is shown in your desired output.

Output:

/path/to/production.json tire_id: 213275925375485 appID: 233262274090443
/path/to/production2.json tire_id: 1815123428733289 appID: 18412365908966538

/path/to/production.json and /path/to/production2.json are just placeholders.

This obviously requires a lot of modification as you'd have to grep each file separately and use an echo command substitution for each one. I'm only including it if you insist upon using grep or if in the future, it's not a json file.

Answer 3

With a sed script :

grep -e tire_id -e appID /path/to/*/vehicle/production.json | sed -n '/\(.*:\)/h;n;s/.*n://;H;g;s/\n//;p'

Retrun

/path/to/000001_000002/vehicle/production.json:    "tire_id": "1305436516186552",        "appID": "1164562920689523",
/path/to/000001_000079/vehicle/production.json:    "tire_id": "1815123428733289",        "appID": "18412365908966538",
/path/to/000001_000088/vehicle/production.json:    "tire_id": "138477888324",

it works if each line "tire_id" is followed by a line "appID". Otherwise, you need a more complex sed script

Answer 4

This command will work even if in a file it misses a "tire_id" or "appID" line. It will not be displayed :

grep -e tire_id -e appID /path/to/*/vehicle/production.json | sed -n 's/\(tire_id\)/\1/;T;h;n;s/.*n:.*\(appID\)/\1/;T;H;g;s/\n/ /;s/"//g;s/,//g;p'