I have a file like:


Now I want to return only lines that end with .foo, but I want to rename all occurrences of file with blag. In this case that means skipping over file.bar entirely. How do I go about doing it with just sed? Essentially what I'm doing currently is:

grep '\.foo$' input | sed -e's/file/blag/'

But I would like to cut the grep out.

This question is roughly based on a pipeline I made for this answer


Or, in mirror form, turn default-printing off, do the replacements, then only print lines you want:

sed -n  's/file/blag/; /\.foo$/p' < input

Or, filter on the desired lines first, then do the replace-and-print:

sed -n '/\.foo$/ { s/file/blag/; p }' < input
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  • I think I would go with my own answer because the one that I think answers the title and is what I was looking for is to filter the desired lines first. If there is no implementation differences, I think sed -n '/\.foo$/ { s/file/blag/; p }' is more difficult to follow than sed -e'/\.foo$/!d' -e's/file/blag/' But you still have the upvote. – Evan Carroll Jul 22 '18 at 17:24

I was able to get grep out of my pipeline to sed by using !d

sed -e'/\.foo$/!d' -e's/file/blag/' ./input

Answer sourced from this forum post

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  • 1
    Because of the lack of anchoring, this would output a line with thefile.food as theblag.food. – Kusalananda Jul 7 '18 at 20:20
  • @Kusalananda yep, fixed -- this is MVP (minimal problem to show an example). As a side note the actual use case needs to be unanchored (link in question) – Evan Carroll Jul 7 '18 at 21:06

Select lines that end in .foo and execute a substitution for only those lines:

sed '/\.foo$/{s/file/blag/}'


$ echo $'file.foo\nfile2.foo\nfile.bar\nfile3.foo' | sed '/\.foo$/{s/file/blag/}'
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sed -n 's/\(file\)\(.*\)\(\.foo\)/blang\2\3/p' input.txt > output.txt

(writes to output file)


sed -i 's/\(file\)\(.*\)\(\.foo\)/blang\2\3/' input.txt 

(in-file replacement)

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