0

Problem..{ I've users with home dirs in /home, so I can get a list of users matching my criteria with following command.

STEP 1: Fetching A List Of Users

du -h --max-depth=1 /home 2>/dev/null | egrep -v '(!G|.cp)' | awk -F"/" '{print $NF}'

Note: The extended grep pattern is my requirement because home dirs contain extra files that need be inversely greped, Also the !G symbolizes that I need a list of partial users those have data less than 1G.

STEP 2: Fetching A List Of Suspended Users

ls -al /somedir/ | grep -v 'lock'

STEP 3: Need To Compare Those 2 Lists & Get Lines In File 1, that are not present in File 2

So I'm stuck on this step, I've tried uniq & diff command, but I'm not getting list of users meeting my criteria.

PS: The command that should compare both files should not compare these files line against line, but rather overall, so any line that is in file 1 & missing in file 2 should be the output for me.

closed as unclear what you're asking by roaima, Jeff Schaller, schily, G-Man, Satō Katsura Jul 4 '18 at 16:25

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • What does the filenames of the suspended users' lock files look like? – Kusalananda Jul 2 '18 at 13:22
  • @Kusalananda it was to skip lock files, cause in that directory there are 2 files associated with single user, so I want userame just one time, so inverse greping does the trick for me. But it's not that important. I want to read file 1 which is output of first command. And file 2 output of 2nd. Compare them and send all entries in file 1 that do not exist in file2. – Sollosa Jul 2 '18 at 13:43
1

Ok I researched a little bit and the solution I was looking for is this

comm -23 <(sort File1) <(sort File2)
1

Use parentheses to group the two command as one:

( du -h --max-depth=1 /home 2>/dev/null | egrep -v '(!G|.cp)' | awk -F"/" '{print $NF}' ; ls -al /somedir/ | grep -v 'lock' ; ) | sort | uniq

The output of the two commands in the parenthese is concatenated and appears as the output of one single process (the subshell).

PS: Your first command outputs /home among the directories...

  • I want all words in file1 that are not in file2 and want to skip remaining ones. Don't want to fetch anything common at all. – Sollosa Jul 2 '18 at 12:44
1

Rather than going through two generated files, iterate over the longer list of usernames and test them against the other directory:

for userpath in /home/*/; do
    user=$( basename "$userpath" )
    if [ ! -e "/somedir/$user" ]; then
        printf 'User %s is not suspended\n' "$user"
    fi
done

This would iterate over all subdirectories in /home and test each directory's basename (the username) against names in /somedir. If there is no corresponding name in that other directory, the user is not suspended.

0

If you want to list all the lines/words in a file that are not in the other:

grep -v -f {smallfile} {bigfile}

Not the answer you're looking for? Browse other questions tagged or ask your own question.