Just wondering if this:
if [ "$first_arg" == "major" ] || [ "$first_arg" == "minor" ]; then exit 1; fi
is the same as this:
if [ "$first_arg" == "major" || "$first_arg" == "minor" ]; then exit 1; fi
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They're not the same. In fact
[ "$first_arg" == "major" || "$first_arg" == "minor" ] is not even a valid expression.
This is because
[ is a command that's equivalent to
test and they can't use the
|| alternative, which operates on the inter-command level. What could be historically considered correct for alternative is
-o, but it's now marked as obsolete by POSIX1, which advises to rewrite
test "$1" -o "$2"
test "$1" || test "$2"
Apart from the
[ constructs, there's also the "modern"
[[ test command, which in turn doesn't accept
-o altogether, but instead accepts
Thus all of these are valid and equivalent:
if [[ $first_arg == major || $first_arg == minor ]]; then exit 1; fi
if [[ $first_arg == major ]] || [[ $first_arg == minor ]]; then exit 1; fi
[ tests (the standard equivalent):
if [ "$first_arg" = major ] || [ "$first_arg" = minor ]; then exit 1; fi
Double quotes aroung
$first_arg are not necessary inside
[[, as there's no word splitting nor pathname expansion in there. The quotes should be used with
[, however. And there's no point in quoting
major either. Not just here, but with
[ too. That's because they're simple strings.
1. See APPLICATION USAGE.
Since both of your expressions are not valid, there is a quasi equivalence ;-)
== is only valid with the non-standard
In general: when using the
test builtin, it is recommended to use only simple expressions as larger expressions could result in unpredictable results in case that parameter expansion applies.
test is built into the shell since approx. 35 years, calling more simple
test commands and combine them at shell level is not a performance problem anymore.