Remove all but latest version - no timestamp

Question

I have a large collection of files that look like this:

Some Name da-1234567-1.py
Some Name da-1234567-2.py
Some Name da-1234567-4.py
Other Name di-5678912-3.py
Other Name di-5678912-4.py
Other Name di-5678912-5.py

I would like to remove all versions and only keep:

Some Name da-1234567-4.py
Other Name di-5678912-5.py

I realise my question is similar to Find latest folder/file version and remove - no time stamp data . However its answer does not work for me and my knowledge of bash and/or regular expression is insufficient to change the solution to cater my needs. Unfortunately I do not have the reputation score to comment thus I do not see another option than to post a new question.

I tried the following from above question:

for file in *.*
do
  [[ -d "$file" || $file =~ _[[:digit:]]{3}\. ]] && continue
  echo -n "Considering $file: " >&2

  extn="${file/*.}"
  versions=("$file")
  keep="$file"

  # Look at matching files
  for version in "${file%.$extn}"_???."$extn"
  do
      [[ -f "$version" ]] || continue

      # Save every one. Identify the current last
      versions+=("$version")
      keep="$version"
      echo -n "$version " >&2
  done
  echo "==> keep $keep" >&2

  # Delete them all except the last
  for version in "${versions[@]}"
  do
      [[ "$version" != "$keep" ]] && echo rm -f -- "$version"
  done
  [[ "$keep" != "$file" ]] && echo mv -f -- "$keep" "$file"
done

I realise that it probably goes wrong in this part: $file =~ _[[:digit:]]{3}\., since opposed to the above question my file ending is -n and not _nnn, but I do not see how to fix it.

Answer 1

Software tools one-liner, using ls -v and sort -V which sort by version number:

{ ls -Qrv *.py |rev | uniq -f 1 | rev; ls -Q *.py; } | sort -V | uniq -u | xargs rm

Using uniq -f 1 depends on the file naming format being consistent -- the surrounding revs are needed because -f has no other way of ignoring the last field.

Answer 2

With zsh:

# all *.<number>.py files in "n"umerical order
files=(*-<->.py(n))

# associative array whose key is the part before the last "-"
typeset -A latest
for f ($files) latest[${f%-*}]=$f

# plain array with the values of the associative array
keep=($latest)

# array subtraction:
echo rm -- ${files:|keep}

(remove echo if happy).

That makes no assumption on what characters the rest of the file names may contain. With bash (or zsh or ksh) and GNU tools:

xargs -r0a <(printf '%s\0' *-*.py |
  grep -zEe '-[[:digit:]]+\.py$' |
  sort -zrV |
  awk -vRS='\0' -vORS='\0' '
    {key = $0; sub(/-[^-]*$/, "", key)}
    seen[key]++') echo rm --