How to execute the following commands in a bash script?

Question

I am working in the following scripto to activate the front end and back end of my project as follows:

#!/bin/bash
cd /Users/perf-fe/
source my_project_34/bin/activate
npm start 
&&
cd /Users/perf-be/
export FLASK_APP=router.py
flask run

However it is not working, It is showing just the first part:

#!/bin/bash
cd /Users/perf-fe/
source my_project_34/bin/activate
npm start 
&&

Since the first process occupies the entire terminal, I would like to appreciate suggestions

Answer 1

You probably want to start the first process in its own job, and then execute the second:

cd /Users/perf-fe/
source my_project_34/bin/activate
npm start &
cd /Users/perf-be/
export FLASK_APP=router.py
flask run

The & tells the shell to run the previous command as a background job, and to continue with the next command even though the prior is still running.

This is distinct from &&, which is a syntax error as you present it. Its use is between two commands, to execute the second if and only if the exit code of the first is zero.