Pass params for getopt from a script that does not use getopt

Question

I have a script (let’s call it scriptC) that uses getopt to parse short and long options and works fine.

This script is being called like this:
scriptA runs scriptB which calls scriptC with the proper parameters.

Question: Is it possible to pass the same parameters as arguments to scriptA and then those be passed over eventually to scriptC?
The scripts are called like:
scriptB "$@" and in scriptB it eventually does scriptC —param1 —param2

Answer 1

If scriptA calls scriptB like

scriptB "$@"

then the command line arguments that were used for invoking scriptA will be passed to scriptB provided that these have not been altered before the call.

Likewise for the call from scriptB to scriptC.

As long as scriptA and scriptB does not try to interpret, change or otherwise mutate the contents of $@ (or the individual positional parameters $1, $2, $3 etc.), the command line arguments will be passed on to scriptC for it to parse with getopt.

---

Example using functions instead of scripts (it works the same way):

#!/bin/sh

scriptC () {
    printf 'Arg: %s\n' "$@"
}

scriptB () {
    scriptC "$@"
}

scriptA () {
    scriptB "$@"
}

scriptA -param1 -param2

This will produce the output

Arg: -param1
Arg: -param2

Doing the call as

scriptA "hello world" --param1 /etc/passwd --param2

will produce

Arg: hello world
Arg: --param1
Arg: /etc/passwd
Arg: --param2

That is, the parameters will be passed on to scriptC without modification. It is then left to scriptC to interpret the parameters using getopt, getopts or by some other means.