Bash scripting for a lab

Question

Doing a class with writing a bash scrip for diagnostics.

the bit i'm completely stuck on is how to i only capture a specific line and segment of text in that line.

IE: if i do an ifconfig

 [user@localhost ~]$ ifconfig
 ens33: flags=4163<UP,BROADCAST,RUNNING,MULTICAST>  mtu 1500
        inet 192.168.88.140  netmask 255.255.255.0  broadcast 192.168.88.255
        inet6 fe80::fbaa:d42c:24db:dca7  prefixlen 64  scopeid 0x20
        ether 00:0c:29:bc:c1:4d  txqueuelen 1000  (Ethernet)

I would like bash to capture line 2 column 12 to 27 for ipv4 address into a $string, and continue to do the same for netmask, broadcast, mac address and ipv6 address/cidr...
also do the same to get out any nameservers in the resolve.conf file.

I then of course have to repeat this for each interface...

Unless someone can reccomend a better way of doing this.

I also am wondering if there is a way i can insert a $string to the ifcfg-ens33 file to change the IP address (and everything else) or am i best off completely recreating the file?

i think with this information i should be able to do the rest of the prac quite easily

EDIT: I can see i need to do something with fields, but i can work out how to make it only do field 2 of line 2 into $ipv41

EDIT2: i have come up with this after more reading. but i cant get the output to go into the variables so far. tried echo, printf, >, >>, >>>

#import settings from ip command
#discover interface type into string
/sbin/ip -o -4 addr show up primary scope global| awk '{print $2}' | echo > 
$if1

#discover interface ipaddress by interface type into strings
/sbin/ip -o -4 addr show $if1 | awk '{print $4}' | echo > $ipv4
/sbin/ip -o -4 addr show $if1 | awk '{print $6}' | echo > $bast
/sbin/ip -o -4 addr show $if1 | awk '{print $9}' | echo > $dhcp
/sbin/ip -o -6 addr show $if1 | awk '{print $4}' | echo > $ipv6

#print discovered info to screen
echo -e "---- Interface     = $if1"
echo -e "---- DHCP Enabled?   $dhcp"
echo -e "---- IPv4 Address  = $ipv4"
echo -e "---- Broadcast     = $bast"

Answer 1

Well there's always head, tail and cut, but this might be easier:

echo `ifconfig wlo1` | 
{ read a b c d e inet f netmask g broadcast h inet6 i ; echo $inet $inet6 ; }

Output:

192.168.1.120 fe80::b400:3b2e:a40a:9f19

Notes:

• read names and sets the variables in one shot. The a b c d e etc. are dummy variables used to absorb the unwanted ifconfig output.

• As soon as the } is run, the variables cease to exist. So put any code that uses those variables before the }.

Answer 2

Try this:

ifconfig -a | tr -s ' ' | awk -F ' ' '{if (/^[a-z]/) printf  $1 " "} {if (/inet /) print " " $3" "$5" "$7} {if (/ether/) print " " $2"}'