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I've a string something like this: abdh0chjkj0g. I want to delete the second last character only if it is a 0.

  • Should all zeros be removed from rcaoe0aoea0o and all B from aoBoaeBo? or is only the second to last character or zeros in general? – Kusalananda Apr 2 '18 at 11:48
  • Hi, Only the 'zero' present in the second last position needs to be removed. Thanks – User123 Apr 2 '18 at 11:49
2

Using :

$ echo 'abdhchjkj0g' | sed 's/0\(.\)$/\1/'

Using :

$ echo 'abdhchjkj0g' | perl -pe 's/0(?=.$)//'

Using :

$ echo 'abdhchjkj0g' | awk '{print gensub(/0(.)$/, "\\1", "1")}'


abdhchjkjg
  • I don't think this quite does what is asked for yet (I think because the example doesn't match the question) - you'll need to pull all 0s to match the question. For example, I think, dsgf0dsfads0d0d would need to become dsgfdsfadsdd – cunninghamp3 Apr 2 '18 at 11:46
  • OP says : the second last character – Gilles Quenot Apr 2 '18 at 11:48
  • Then continues to say "from the string everytime it appears" – cunninghamp3 Apr 2 '18 at 11:50
  • And, as far as I can interpret his comment, only if it is a zero. – Kusalananda Apr 2 '18 at 11:51
  • @cunninghamp3 Possibly with the qualifier "at that position". Note "everytime", not "everywhere". – Kusalananda Apr 2 '18 at 11:52

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