So the following grep matches 2 lines.

grep -w testfile.csv,Jim,Jonson,000000,George,Doe,FFFFF

How can I make it match exactly and only the specific word? In this example only
Let's assume that whitespace in the beginning or next to the comma separator may appear and I would like this to be if possible cross platform grep.

  • should it match this - – RomanPerekhrest Mar 27 '18 at 14:28
  • @RomanPerekhrest:No. No prefix or suffix – Jim Mar 27 '18 at 14:30
  • Here's gnu definition for word and non-word characters:-w Select only those lines containing matches that form whole words. The test is that the matching substring must [...] be either at the end of the line or followed by a non-word constituent character. Word-constituent characters are letters, digits, and the underscore. As you can see it's quite different than your definition of non-word ... And btw, an unescaped dot matches any character so your grep -w would also match 1a2b3c4 – don_crissti Mar 27 '18 at 14:38
  • @don_crissti:I want to demark it within the 2 , then – Jim Mar 27 '18 at 14:46
  • 1
    for given sample, awk -F, '$1==""' should work.. if not, please add some more samples – Sundeep Mar 27 '18 at 14:47

As noted by don_crissti in comments. The issue in your case is that the pattern trying to match does not match the word conditions met for -w

Use the PCRE mode in your GNU grep if its supported. Using a positive lookahead

grep -P '^1\.2\.3\.4(?=,)' file

or as recommended by Sundeep without using PCRE just do

grep '^1\.2\.3\.4,' file

Also for more exact string match, awk is easier to do

awk -F, -v var="" '$1==var' file
  • So with awk I avoid the issues with the regex and escaping . etc? – Jim Mar 27 '18 at 21:03
  • @Jim : Yes! That’s right. – Inian Mar 27 '18 at 21:21
  • I'll add a recommendation for grep '^ *1\.2\.3\.4 *,' testfile.csv as trailing whitespace is apparently allowed. – Jeff Schaller Mar 28 '18 at 0:59

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