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I am trying to use find . -type d -print | wc -m where -m or --chars would print the character counts of the folder names.
Take following screen shot as example, the character count for tempFolder + tempFolder + dingdongFolder is only 34, and event counting the slashes and dots is still 40. Why the command print out 43 characters? Where are the 3 extra characters come from?
find . -type d -print | tr -d '\n' | wc -m
tr will delete all newline characters and wc will count number you want.
Apparently trailing newlines are counted as a character also.
Suppose you want the character count per directory, you can do
$ find -type d -exec bash -c 'echo -n $0 | wc -m' {} \;
1
12
27
Which adds up to the 40 that you are looking for. Note that the echo -n removes the trailing newlines.
Summing these three is also possible.
$ find -type d -exec bash -c 'echo -n $0 | wc -m' {} \; | awk '{S+=$1} END {print(S)}'
40
Peter.O : Rush : Bernhard ... real 1.00 : 1.01 : 193.36, user 1.00 : 1.26 : 702.53, sys 1.00 : 1.01 : 109.76... The fastest times (for 100 itterations) were: real 3.699 , user 1.120 , sys 1.120
– Peter.O
Jul 18 '12 at 12:34
Set a bash/ksh/zsh array ct to the output of wc -lm, then use shell arithmetic.
ct=($(find . -type d -print |wc -lm)); echo $((ct[1]-ct[0]))
Or use field splitting and positional parameters:
set $(find . -type d -print |wc -lm); echo $(($2 - $1))
