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How to make a variable containing all the rest parameter from nth particular parameter, for instance the string holds all data from 3rd parameter until 9th parameter is within a variable named $a... Thanks in advance.

  • How should the parameters be separated in the variable? Spaces? Pipe? – Jeff Schaller Feb 15 '18 at 10:56
  • as usual; space that's not surrounded by (double) quotes – abdan Feb 15 '18 at 10:59
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In Bash/ksh/zsh, you can use something like ${@:3:7} to get the 3rd to 9th parameters as distinct words, or ${*:3:7} to get them concatenated with the first character of IFS as joiner. (7, since there's seven in total from 3 to 9.)

so:

$ set -- $(seq 11 21)
$ echo "${*:3:7}"
13 14 15 16 17 18 19

or

$ a="${*:3:7}"

However, if you want to pass those arguments as parameters to another command, use "${@:3:7}" directly on the command line in question, i.e.

somecmd "${@:3:7}"

If you need to do this in standard shell, you can't use ${var:n:m}. Instead you would need to shift the first arguments away, and then use "$@", so:

arg1=$1
arg2=$2
shift 2
somecmd "$@"

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