2

I have some C source code which was originally developed on Windows. Now I want to work on it in Linux. There are tons of include directives that should be changed to Linux format, e.g:

#include "..\includes\common.h"

I am looking for a command-line to go through all .h and .c files, find the include directives and replace any backslash with a forward slash.

7

find + GNU sed solution:

find . -type f -name "*.[ch]" -exec sed -i '/^#include / s|\\|/|g' {} +
  • "*.[ch]" - wildcard to find files with extension .c or .h
  • -i: GNU sed extension to edit the files in-place without backup. FreeBSD/macOS sed have a similar extension where the syntax is -i '' instead.
  • /^#include / - on encountering/matching line which starts with pattern: #include
  • s|\\|/|g - substitute all backslashes \ with forward slashes / (\ escaped with backslash \ for literal representation).
  • You might want to change your qualification regex to /^#\s*include\W/, because you can have whitespace after the #, and the whitespace (which can include tabs) after include is optional (e.g., # include"..\includes\common.h" is legal).  Also, I just did a quick test, and, to my surprise, whitespace before the # was also allowed — I don’t know whether that’s standard.  If it is, then /^\s*#\s*include\W/. – Scott Jan 29 '18 at 21:31
-2

I have done by below command

input.txt

#include "..\includes\common.h"

command:

 sed 's/\\/\//g' input.txt

output

#include "../includes/common.h"
  • 1
    Kindly let me know why down voted for my answer – Praveen Kumar BS Jan 28 '18 at 14:33
  • 1
    There are no matching conditions in your command...it will replace any instance it faces. – Saeid Yazdani Jan 29 '18 at 10:23

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