awk to find the multiple pattern in a line

Question

I have file file1.txt /file2.txt When I run the awk command with boundary search between "Type header call_header " and "END" it print the lines below END also . Example :-

File1.txt

Type header call_header 
abc , def , ghi , 
jkl ,mno 
END 
Define call_header 
type as call_header 

Fil2.txt

Type head call_header
data1, data2, voice ,
mms , mms2 
END
Define call_header 
type as call_header

I have tried:

awk '/^Type (header|head) call_header$/,/^END?$/'  {print} file1.txt

However, it is printing other lines also .

Need Below data only :

Type header call_header 
abc , def , ghi , 
jkl ,mno 
END 

Answer 1

Your awk invocation is incorrect:

awk '/^Type (header|head) call_header$/,/^END?$/'  {print} file1.txt

Here, awk would search for a file called {print}.

The whole script should be within the single quotes:

awk '/^Type (header|head) call_header$/,/^END?$/ {print}' file1.txt

Or, alternatively (shortening the first regular expression slightly and getting rid of { print } completely),

awk '/^Type head(er)? call_header$/,/^END?$/' file1.txt

Tested with OpenBSD awk, mawk and GNU awk.

With sed, this is remarkably similar to the above:

sed -nr '/^Type head(er)? call_header$/,/^END?$/p' file1.txt