1

I have a backup script which is creating two files:

a) db_mywebsite_2018-01-10_00-25.sql.gz (150 MB)

b) mywebsite1_2018-01-10_00-01.tar.gz (2 GB)

I want to remove the date (XXXX-XX-XX_XX-XX) from file names. Because the backup is made daily, each file will have a different date in the name. For this, I'm using the following command:

rename -v -n 's/_\d{4}-\d{2}-\d{2}_\d{2}-\d{2}//' *.sql.gz

For testing, I have touched two files db_mywebsite_2018-01-10_00-25.sql.gz and mywebsite1_2018-01-10_00-01.tar.gz

Command:

rename -v -n 's/_\d{4}-\d{2}-\d{2}_\d{2}-\d{2}//' *.sql.gz

Output:

db_mywebsite_2018-01-10_00-25.sql.gz renamed as db_mywebsite.sql.gz

1. The problem is that despite the above message "db_mywebsite_2018-01-10_00-25.sql.gz renamed as db_mywebsite.sql.gz" when I check it via ls -l it looks like that file name hasn't been renamed.

2. Rename command (regex) is not working on file mywebsite1_2018-01-10_00-01.tar.gz.

4
  1. For the perl version of rename, the option -n means no action: print names of files to be renamed, but don't rename. If you want the file to be renamed, don't use the -n option. Thus, instead of:

    rename -v -n 's/_\d{4}-\d{2}-\d{2}_\d{2}-\d{2}//' *.sql.gz
    

    Use:

    rename -v 's/_\d{4}-\d{2}-\d{2}_\d{2}-\d{2}//' *.sql.gz
    
  2. Consider:

    rename -v -n 's/_\d{4}-\d{2}-\d{2}_\d{2}-\d{2}//' *.sql.gz
    

    The above command will only attempt to rename files ending in .sql.gz. It will not to rename mywebsite1_2018-01-10_00-01.tar.gz because that file ends with .tar.gz. To rename both files, try:

    rename -v -n 's/_\d{4}-\d{2}-\d{2}_\d{2}-\d{2}//' *.tar.gz *.sql.gz
    
  • 1
    +1. -n is for debugging/testing your regex without making potentially irreversible changes to your filenames. i.e. it's a --dry-run option. – cas Jan 11 '18 at 6:13

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.