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Suppose in unix directory,there are some files placed with same filename but with different extension like

abc.001
abc.002
abc.003

There can be n number of files.

I need to first get the files from the directory and then iterate on each files. With the below command I am getting the files but can anyone please help how to iterate on each file and read each file and do processing.?

find "/tmp/files/" -name "abc.*" -type f -exec echo {} \;
  • what kind of processing are you planing to perform? – RomanPerekhrest Jan 3 '18 at 14:06
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    @RomanPerekhrest:- After I get the list of files I need to iterate on all files and grep for particular value. – user6376225 Jan 3 '18 at 14:11
  • If the file names are the same save for extensions AND the extensions are 3 byte numbers: for f in abc.*; do [[ "$f" =~ "abc."[0-9]{3} ]] && echo "Processed: $f"; done – Stan Strum Jan 3 '18 at 17:51
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Why iterate? grep takes several file arguments at once, so

grep PATTERN abc.*

should work.

In case the files are not all in the same directory, using find is an option:

find /tmp/files -name 'abc.*' -type f -exec grep PATTERN /dev/null {} +

The + at the end tells find to pass as many files as possible to grep in one go. The /dev/null is to make sure at least 2 files are passed to grep so grep always outputs the file name for every match. With GNU grep, you can use the -H (aka --with-filename) option instead.

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