I am listing files from a folder and taking an input from the user to select one of the files.
files=$(ls ~/VideoExtract/*.avi) i=1 for j in $files do echo "$i.$j" file[i]=$j i=$(( i + 1 )) done echo "" echo "" read -p "Enter the serial number from the above list : " input clear
Suppose if I have 3 files, the above code lists all three files listed with serial numbers 1,2,3. I want to validate if the user provides the correct input and not break the code till receiving a correct input. To do this, I have used a while loop after the above code
while [[ "$input" =~ ["$i"] ]] do echo "Please provide a serial number from the list given below." files=$(ls ~/VideoExtract/*.avi) i=1 for j in $files do echo "$i.$j" file[i]=$j i=$(( i + 1 )) done read -p "Enter the serial number from the above list : " input done
This does returns the list of files again. The problem is, if I have 3 files, and if I type 4, the loop continues to work, but if I provide 5 instead, the loop breaks and moves on to the next line of the code. I am not sure if the problem is in line
while [[ "$input" =~ ["$i"] ]]
i=$(( i + 1 ))
=~ I have tried with
! $input == $i and similar other combinations, such as with and without  for $i. Nothing seem to work.
How do I run the while loop till the time the user provides a valid input that is within the range of $i.