0

I have a script like this:

#!/bin/bash
curl --request POST --url http:/myUrl.com/etc --header 'content-type: application/json' --data '{"myId": $1, "services": {"ENABLE_THE_SERVICE": "1"}}';

Then when I try to run: ./myScript.sh 77777 there is an error like:

{"code":"BAD_REQUEST","message":"[line: 1, column: 17] Unexpected character ('$' (code 36)): expected a valid value (number, String, array, object, 'true', 'false' or 'null')\n at [Source: org.jboss.resteasy.core.interception.MessageBodyReaderContextImpl$InputStreamWrapper@45771071; line: 1, column: 17]"}

Do you know how to make it work? thanks..

1

Don't single-quote the string that contains the $1, that will stop the shell from expanding it.

Instead:

curl --request POST \
    --url 'http:/myUrl.com/etc' \
    --header 'content-type: application/json' \
    --data '{"myId": '"$1"', "services": {"ENABLE_THE_SERVICE": "1"}}'

This ends the first part of the data string just before the $1, then double quotes the $1 itself, and concatenates that with a new single-quoted string with the rest of the data content.

This assumes that the string in $1 is already a JSON-encoded string. If it is not, you may want to use jq to construct the data payload:

curl --request POST \
    --url 'http:/myUrl.com/etc' \
    --header 'content-type: application/json' \
    --data "$( jq -nc --arg id "$1" '{"myId": $id, "services": {"ENABLE_THE_SERVICE": "1"}}' )"

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.