I was searching for a way to convert hexadecimal via command line and found there is a very easy method
It's working great but I'm a little confused as to what is happening here.
$(...) is normally a sub-shell, where the contents are evaluated before the outer command.
Is it still a sub-shell in this situation? I'm thinking not as that would mean the sub-shell is just evaluating
(0x63) which isn't a command.
Can someone break down the command for me?