having issues greping variables in linux

Question

Below is the code I am trying:

{    
echo "Enter dirname and hit Return"
read input1
echo "Enter a pattern to be searched for in the current directory"
read input2
find /*/${input1}/*/logs/*/*/*/* -name '*.gz' -exec sh -c 'gzip -cd "$0" | grep -- "${input2}"' {} \;
}

while the input1 matches but the input2 doesnt seem to match and I am getting all the outputs of input1 without getting input2 matched with it.

purpose is to read all the .gz files and get the keyword input2 match.

Answer 1

The "internal" script that find calls does not have access to the $input2 variable.

You may instead do

find /*/"$input1"/*/logs/*/*/*/* -name '*.gz' \
    -exec sh -c 'gzip -cd "$1" | grep -e "$0"' "$input2" {} \;

This passes the value of $input2 into the internal script and will make it available as $0 while the filename argument will be $1.

Alternatively, just let find decompress the files and filter the output from find as a whole:

find /*/"$input1"/*/logs/*/*/*/* -name '*.gz' \
    -exec gzip -cd {} + | grep -e "$input2"

---

Since find already enters into all subdirectories of the given top-directory, you can probably leave out some of the filename globs and instead use -mindepth 4 (if your find supports this option), and add -type f to signal that you're only interested in regular files:

find /*/"$input1"/*/logs -mindepth 4 -type f -name '*.gz' \
    -exec gzip -cd {} + | grep -e "$input2"