Counting occurrences of word in text file

Question

I have a text file containing tweets and I'm required to count the number of times a word is mentioned in the tweet. For example, the file contains:

Apple iPhone X is going to worth a fortune
The iPhone X is Apple's latest flagship iPhone. How will it pit against it's competitors?

And let's say I want to count how many times the word iPhone is mentioned in the file. So here's what I've tried.

cut -f 1 Tweet_Data | grep -i "iPhone" | wc -l

it certainly works but I'm confused about the 'wc' command in unix. What is the difference if I try something like:

cut -f 1 Tweet_Data | grep -c "iPhone"

where -c is used instead? Both of these yield different results in a large file full of tweets and I'm confused on how it works. Which method is the correct way of counting the occurrence?

Answer 1

Given such a requirement, I would use a GNU grep (for the -o option), then pass it through wc to count the total number of occurrences:

$ grep -o -i iphone Tweet_Data | wc -l
3

Plain grep -c on the data will count the number of lines that match, not the total number of words that match. Using the -o option tells grep to output each match on its own line, no matter how many times the match was found in the original line.

wc -l tells the wc utility to count the number of lines. After grep puts each match in its own line, this is the total number of occurrences of the word in the input.

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If GNU grep is not available (or desired), you could transform the input with tr so that each word is on its own line, then use grep -c to count:

$ tr '[:space:]' '[\n*]' < Tweet_Data | grep -i -c iphone
3

Answer 2

Easiest Method is,

grep -wc "your_text" FileName

for you it wil be,

grep -wc "iPhone" Tweet_Data