I have a web application that access a remote storage running Linux to get some files, the problem is that the remote storage have currently 3 million files , so accessing the normal way is a bit tricky.
So I needed to work on a script that is going to make it a little bit more easy to use , this script is going to reorganize the files into multiple folders depending on their creation date and specially their names,i made the script and it worked just fine, it intended to do what it meant to do, but it was too slow, 12 hours to perform the work completely
(12:13:48 to be precise).
I think that the slowness is coming from the multiple
rev calls I make.
I get the file names with an
ls command that I loop into with for, and for each file I get the parent directory and, depending on the parent directory, I can get the correct year:
case "$parent" in ( "Type1" ) year=$(echo "$fichier" | rev | cut -d '_' -f 2 | rev );; ( "Type2" ) year=$(echo "$fichier" | rev | cut -d '_' -f 2 | rev);; ( "Type3" ) year=$(echo "$fichier" | rev | cut -d '_' -f 1 | rev | cut -c 1-4);; ( "Type4" ) year=$(echo "$fichier" | rev | cut -d '_' -f 1 | rev | cut -c 1-4);; ( "Type5" ) year=$(echo "$fichier" | rev | cut -d '_' -f 1 | rev | cut -c 1-4);; esac
for type1 of files :
I need to get the year so I perform a reverse cut:
year=$(echo "$file" | rev | cut -d '_' -f 2 | rev );;
for type2 of files :
and then I can
mv the file freely :
mv $file /some/path/destination/$year/$parent
and yet this is the simplest example, there are some files that are much more complex, so to get 1 information I need to do 4 operations,
1 echo , 2rev and 1echo.
While the script is running I am getting speeds of
50 files/sec to 100 files\s, I got this info by doing a
wc-l output.txt of the script.
Is there anything I can do to make it faster? or another way to cut the files name? I know that I can use
awk or string operations but I did not really understand how.