My file data Pattern is below and i need output as 6 or 3 or 8 or 4 based on the variable value which is eth0 and eth1


Below code works well

sed 's/.*eth0RX:\([0-9]\+\).*/\1/g' $EMSTATE/packetdrop.txt

But fails when I use dynamic variable like below

rxfile=sed 's/.*$iRX:\([0-9]\+\).*/\1/g' $EMSTATE/packetdrop.txt
  1. Inside single quotes, everything is what it is.  $i is a dollar sign followed by an i.  If you want to use a variable, you have to put the string into double quotes, somewhat like this:
  2. But that won’t work, because it will look for a variable called iRX.  The simplest way to fix that is to put the variable name in braces, like this:
  3. You should put $EMSTATE into double quotes, too.  You can use "$EMSTATE"/packetdrop.txt or "$EMSTATE/packetdrop.txt", whichever you prefer.
  • Yes, there is a significant overlap.   (My answer is not the same as yours, or a subset, as you didn’t mention my point #3.)   But, more importantly, I started typing my answer before you posted yours.  And I believe that my explanation is somewhat clearer than yours. – Scott Oct 2 '17 at 6:16

Variable expansion doesn't happen in single quoting. Use double quote instead. And if you want to set result to a variable, you need to run sed within command substitution syntax $(...) and better to quote this as well "$(...)". Plus as $iRX can be a valid variable name better do ${i}.

rxfile="$(sed "s/.*${i}RX:\([0-9]\+\).*/\1/g" "$EMSTATE/packetdrop.txt" )"

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