1

How can I sort of list current directory contents (including sub-directories recursively) (which is under svn) files info (path relative to current dir)?

I want this to get log in format like:

none|main.lua
none|src/main.h

I wonder if it is possible and how to do such thing using svn and bash?

Improve this question
4
  • I want to create such log in order to create an image using gource that would represent actual state or current revision svn files. so I would just add none as user name, 0 as timestamp, A as type.
    – user1078642
    May 26, 2012 at 22:37
  • if it's just the relative path, have you considered using find? For the relative path, with bash you have the globstar (disabled by default, but just a shopt -s globstar away).
    – njsg
    May 26, 2012 at 23:02
  • 1
    I don't understand whether you're trying to list all files in your working copy or just the files under svn, nor where the none comes from (why not a user name? and why do you mention a timestamp and a type in your comment, there aren't any in your sample output).
    – Gilles 'SO- stop being evil'
    May 28, 2012 at 1:19
  • If you need this for gource, the wiki of gource has a page that explains how to use it with subversion code.google.com/p/gource/wiki/SVN
    – janos
    Aug 22, 2012 at 9:02

1 Answer 1

Reset to default
1

You may want to start with something like:

find . -name .svn -prune -o -print

This prints out all the files under ., without traversing into any .svn directories. I don't know what the none| part means, but you can pipe the output of find into sed, etc..

Another way is to start with

svn status -v

and filter the output as ncecssary.

Improve this answer

You must log in to answer this question.

Not the answer you're looking for? Browse other questions tagged .