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There are multiple directories under "home" directory. dir1 dir2 dir3 dir4 dir5

I want bash script to recursively archive dir1-2-3 as dir1.zip, dir2.zip & dir3.zip but exclude dir4 and dir5.

Is it doable ?

4

No, Linux removed that feature with the latest release.

Only joking, of course it's doable.

for dir in dir1 dir2 dir3; do
    zip -r "$dir" "$dir"
done

If the directories truly have the same prefix:

for dir in dir[1-3]; do
    zip -r "$dir" "$dir"
done

This assumes that the loop is performed in the correct directory.

If you have many many directories and only want to exclude a few, use bash with its extglob shell option set:

shopt -s extglob
for dir in dir!(4|5); do
   test -d "$dir" || continue
   zip -r "$dir" "$dir"
done

The pattern dir!(4|5) will match any name starting with dir and then continuing with anything not a 4 or a 5. The pattern could also have been written dir!([4-5]) or !(dir4|dir5).

I've also made sure, in the last loop, that any matched name that is not the name of a directory is skipped.

  • Is it possible to Exclude instead of Include ? There are about 50 directories to archive and 3-4 to exclude. – Dhillon Sep 14 '17 at 12:58
  • 1
    use for dir in $(ls | grep -Ev '^(dir4|dir5)$'); do ... – Michael Daffin Sep 14 '17 at 13:03
  • @Dhillon See update. – Kusalananda Sep 14 '17 at 13:11
  • @MichaelDaffin Does not work for all possible names. – Kusalananda Sep 14 '17 at 13:11
  • @Kusalananda dir4, dir5 were just example. Could you please post how to exclude if directories are named as "first, second and third". Regards, – Dhillon Sep 14 '17 at 13:17

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