I was surprised with this comment in other question:
Sending dd the USR1 signal too soon after it has started (i.e. in a bash script, the line after you started it) will in fact terminate it
Can anybody explain why?
Unix & Linux Stack Exchange is a question and answer site for users of Linux, FreeBSD and other Un*x-like operating systems. It only takes a minute to sign up.Sign up to join this community
Each signal has a "default disposition" -- what a process does by default when it receives that signal. There's a table in the
signal(7) man page listing them:
Signal Value Action Comment ────────────────────────────────────────────────────────────────────── ... SIGUSR1 30,10,16 Term User-defined signal 1 SIGUSR2 31,12,17 Term User-defined signal 2
SIGUSR2 both have the default action
Term -- the process is terminated.
dd registers a handler to intercept the signal and do something useful with it, but if you signal too quickly it hasn't had time to register that handler yet, so the default action happens instead