I try to make runwhen perform a job every 6 hours, starting at 3:00 in the morning.
(How) Can this be done?
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found a solution - if somebody else is interested...
#!/bin/sh -e RUNWHEN=",H/6" # The constraint string consists of a sequence of unit constraints. Each unit # constraint consists of a comma, one of the following letters indicating which # unit is constrained: # # * y: year. # * m: month (in the range 1-12). # * d: day of the month (in the range 1-28, 1-29, 1-30, or 1-31, as # appropriate for the month in question). # * w: day of the week (in the range 0-6, with 0 representing Sunday). # * H: hour of the day (in the range 0-23). # * M: minute of the hour (in the range 0-59). # * S: second of the minute (in the range 0-59). # # and finally one of the following: # # * =n: matches times when the given unit is exactly n. # * -n: matches times when the given unit is exactly m, where m+n is one # more than the largest value of the unit. (For example, n+m=24 for H, # so ,H-1 is equivalent to ,H=23. # * /n: matches times when the given unit is divisible by n. exec 2>&1 \ rw-add n d1S now1s \ rw-match \$now1s $RUNWHEN wake \ ## here comes the interesting part rw-add \$wake d3H wake \ sh -c ' echo "@$wake" | tai64nlocal | sed "s/^/next run time: /" exec "$@"' arg0 \ rw-sleep \$wake \ thescript