How to do this with while loop [duplicate]

Question

Problem is:

grep the output of ps aux for any instance of firefox, if firefox is already running, open link in new tab, if firefox is not running, start firefox and open the link.

Point to be noted here is that I have mentioned the count variable to be greater than 1 because ps aux | grep firefox itself is a process that would be listed, so any other instance other than that. When I run the following script it, goes into loop, what's the right logic?

#!/bin/bash
count=0
while [[ $(ps aux | grep firefox) ]]
do
    count=$((count+1)) ;
    if ( count -gt 1 )
        then    
            nohup firefox --new-tab "mega.nz" &
        else
            nohup firefox "mega.nz" &
    fi
done

Edit : Thanks to the comments and answer below, they helped me get rid of the while loop totally by using pgrep as thrig and Deathgrip mentioned below, but how do I achieve this by while loop or let me know if this cannot be performed with while loop.

Answer 1

Why don't you just want something like:

#!/bin/bash
count=0
if [[ $(pgrep firefox) ]]
then    
    nohup firefox --new-tab "mega.nz" &>/dev/null &
else
    nohup firefox "mega.nz" &>/dev/null &
fi

Your script edited, still not sure under what conditions you want to break out of the loop:

#!/bin/bash
count=0
while [[ $(ps aux | grep firefox) ]]
do
    count=$((count+1)) ;
    if [ $count -gt 1 ]
        then    
            nohup firefox --new-tab "mega.nz" &
            break
        else
            nohup firefox "mega.nz" &
    fi
done